Question

A molecule of a gas has six degrees of freedom. Then, the molar specific heat of the gas at constant volume is

• A. $\frac{R}{2}$
• B. $R$
• C. $\frac{3R}{2}$
• D. $2R$
• E. $3R$

Answer 1

The correct option is E $3R$

We know that,
Specific heat of a gas (At constant volume)
$C_v=\frac{f}{2}\times R$
where $R$= gas constant and $f$ = degree of freedom $=6$.
$C_v=\frac{6}{2}\times R=3R$