A molecule of glucose is formed in Calvin cycle from

6CO

_{2}

+ 12 ATP

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6CO

_{2}

+ 18 ATP + 12 NADPH

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6CO

_{2}

+ 18 ATP + 30 NADPH

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6CO

_{2}

+ 30 ATP + 12 NADPH

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Solution

The correct option is C 6CO $_{2}$ + 18 ATP + 12 NADPH
A) 18 ATP and 12 NADPH along with ${6 C O}_{2}$ are required to form one molecule of glucose.
B) ${6 C O}_{2} + 18 A T P + 12 N A D P H$ forms one molecule of glucose.
C) One molecule of glucose requires 12 NADPH.
D) One molecule of glucose requires 18 ATP.
So the correct answer is ' ${6 C O}_{2} + 18 A T P + 12 N A D P H$ '.

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Similar questions

For every CO₂ molecule entering the Calvin cycle, the number of ATP and NADPH required is

C O_{2}

ATP

NADPH

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