A molecule of hydrocarbon 'X' can add upon 2 molecules of $B r_{2} .$ 'X' on ozonolysis gives two different products which can not be further oxidised. Identify 'X'.

H_{2} C = C H - C H = C H_{2}

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H C \equiv C H

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H_{3} C - C \equiv C H

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H_{2} C - C H = C H - C H_{3}

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Solution

The correct option is A $H_{3} C - C \equiv C H$
As the molecule X can add 2 molecules of Bromine, it is an alkyne. From the given options, it can be B or C. Now given that, X on ozonolysis gives two different products , it has to be C as the ozonolysis of B & C can be compared as:
$H C \equiv C H O_{3} - - \to H_{2} O 2 H C O O H$
$C H_{3} - C \equiv C H O_{3} - - \to H_{2} O C H_{3} C O O H + H C O O H$

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