A molecule of mass $m$ of an ideal gas collides with the wall of the vessel with the velocity $v$ and returns back with the same velocity. The change in the linear momentum of the molecule will be:

4 m v

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8 m v

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2 m v

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- 2 m v

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Solution

The correct option is D $- 2 m v$

Initial momentum $= m v$

Final momentum $= - m v$

Change in momentum $= - m v - (m v) = - 2 m v$

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A molecule of mass m of an ideal gas collides with the wall of the vessel with the velocity v and returns back with the same velocity. The change in the linear momentum of the molecule will be:

The correct option is D −2mv Initial momentum =mv Final momentum =−mv Change in momentum =−mv−(mv)=−2mv

A molecule of mass $m$ of an ideal gas collides with the wall of the vessel with the velocity $v$ and returns back with the same velocity. The change in the linear momentum of the molecule will be:

The correct option is D $- 2 m v$

Initial momentum $= m v$

Final momentum $= - m v$

Change in momentum $= - m v - (m v) = - 2 m v$