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Question

# a moles of PCl5 are heated in a closed container to equilibriate PCl5(g)⇌PCl3(g)+Cl2(g) at a pressure of P atm. If x moles of PCl5 dissociate at equilibrium, then:

A
xa=(KpP)12
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B
xa=KpKp+P
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C
xa=(KpKp+P)12
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D
xa=(Kp+PKp)12
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Solution

## The correct option is C xa=(KpKp+P)12PCl5(g)⇋PCl3(g)+Cl2(g)Moles of PCl5 dissociated =xMoles of PCl5 left =(a−x)Moles of PCl3 formed =xMoles of Cl2 formed =xTotal moles =(a+x)Degree of dissociastion α=xaPressure due to PCl5=(1−α)(1+α)PPressure due to PCl3=α(1+α)PPressure due to Cl2=α(1+α)PNow,Kp=XPCl3.XCl2XPcl5P=α21−α2PKp(1−α2)=Kp−Kpα2=α2PKp=(Kp+P)α2⇒α=√KpKp+P=xa⇒xa=√KPKP+P

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