A moment of $200 N m$ required to open the door. Determine the distance of the point of force from the hinged point if a $50 N$ force perpendicular to the radius can just open the door.

1 m

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2 m

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3 m

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4 m

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Solution

The correct option is D $4 m$
Given:
Force applied, $F = 50 N$
Moment of force, $τ = 200 N m$

Let the distance of the point of application of force be at a distance $d$ .
From definition of moment of force,
$τ = F d$
$d = \frac{τ}{F}$
$d = \frac{200 N m}{50 N}$
$d = 4 m$

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A moment of 200 Nm required to open the door. Determine the distance of the point of force from the hinged point if a 50 N force perpendicular to the radius can just open the door.

The correct option is D 4 mGiven: Force applied, F=50 N Moment of force, τ=200 Nm Let the distance of the point of application of force be at a distance d. From definition of moment of force, τ=Fd d=τF d=200 Nm50 N d=4 m

A moment of $200 N m$ required to open the door. Determine the distance of the point of force from the hinged point if a $50 N$ force perpendicular to the radius can just open the door.

The correct option is D $4 m$
Given:
Force applied, $F = 50 N$
Moment of force, $τ = 200 N m$

Let the distance of the point of application of force be at a distance $d$ .
From definition of moment of force,
$τ = F d$
$d = \frac{τ}{F}$
$d = \frac{200 N m}{50 N}$
$d = 4 m$