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Byju's Answer

Standard XII

Physics

Problems with Pseudo Force

A monkey clim...

Question

A monkey climbs up and another monkey climbs downa rope hanging from a tree with same uniformacceleration separately. If the respective masses ofmonkeys are in the ratio 2:3 for same tension inropes, the common acceleration must be 1. g/5 2. g/3 3. g/2 4.

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Similar questions

Q. A monkey of mass

40 kg

climbs up a rope of breaking load

600 N

, hanging from a ceiling. If it climbs up the rope with maximum possible acceleration, then the time taken by the monkey to climb up is:
(Length of the rope is

10 m

and

g = 10 {m/s}^{2}

A monkey of mass

40

k g

climbs on a rope which can stand a maximum tension of

600

N

. In which of the following cases will the rope break. When the monkey

(a) Climbs up with an acceleration of

6

m s^{- 2}

(b) Climbs down with an acceleration of

4

m s^{- 2}

5

m s^{- 1}

(d) Falls down the rope nearly freely under gravity.

(Ignore the mass of the rope)

A monkey of mass 20kg climbs on a rope which can stand a maximum tension of 300 N.in which of the following cases the rope breaks? The monkey

Options

Climbs up with an acceleration of 6m/s2

Climbs up with a uniform speed of 5m/s

Climbs down with an acceleration of 4m/s2

Falls down the rope nearly freely under gravity

Ans :1st option

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A, B

and

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with masses of

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8 k g

respectively are climbing up & down the rope suspended from

D

. At the instant represented,

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C

is pulling himself up with acceleration of

1.5 m / s^{2}

. Monkey

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. Calculate the tension

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in the rope at

D

(g = 10 m / s^{- 2})

A rope which can withstand a maximum tension of 400 N is hanging from a tree. If a monkey of mass 30 kg climbs up the rope, in which of the following cases will the rope break? Take $g = 10 m s^{- 2}$ and neglect the mass of the rope.

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