Question

A monkey is ascending a branch with constant acceleration. If the breaking strength is $160\%$ of the monkey's weight, what is the maximum acceleration permitted for the monkey?

Answer 1

Breaking strength is $160$ percent of monkey’s weight.

$F_S=\frac{160}{100}\times mg$

$F_S=1.6\times mg$

Let maximum permissible acceleration for monkey is$am/s^2$.

So $F_S-mg=ma$

$1.6mg-mg=ma$

$ma=0.6mg$

$a=0.6g$

$a=6m/s^2$