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Byju's Answer

Standard XII

Physics

Second Law of Motion

A monkey of 4...

Question

A monkey of 4 kg mass is climbing up on rope with v= $4 t^{2}$ , find tension in rope at t=5 sec.

40 N

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120 N

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160 N

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200 N

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Solution

The correct option is D 200 N
$v = 4 t^{2}$

$a = \frac{d v}{d t} = 8 t m / s^{2}$ (variable acc.)

at t=5 $s$ , a=40 $\frac{m}{s^{2}}$

for monkey

$f_{n e t} = T - m g = m a$

$T = m g + m a = m (g + a)$

$= 4 (10 + 40) = 200 N$

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A monkey of 4 kg mass is climbing up on rope with v=4t2, find tension in rope at t=5 sec.

The correct option is D 200 Nv=4t2 a=dvdt=8t m/s2 (variable acc.) at t=5 s, a=40 m/s2 for monkey fnet=T−mg=ma T=mg+ma=m(g+a) =4(10+40)=200 N

A monkey of 4 kg mass is climbing up on rope with v= $4 t^{2}$ , find tension in rope at t=5 sec.

The correct option is D 200 N
$v = 4 t^{2}$

$a = \frac{d v}{d t} = 8 t m / s^{2}$ (variable acc.)

at t=5 $s$ , a=40 $\frac{m}{s^{2}}$

for monkey

$f_{n e t} = T - m g = m a$

$T = m g + m a = m (g + a)$

$= 4 (10 + 40) = 200 N$