Question

A monkey of mass $20$ kg is holding a vertical rope. The rope will not break when a mass of $25$ kg is suspended from it but will break if the mass exceeds $25$ kg. What is the maximum acceleration with which the monkey can climb up along the rope ? $(g=10m/s^2)$

• A. $25m/s^2$
• B. $2.5m/s^2$
• C. $5m/s^2$
• D. $10m/s^2$

Answer 1

The correct option is B $2.5m/s^2$

Maximum bearable tension in the rope is
$T=25\times 10=250N$
$T-mg=ma$
$\Rightarrow a=\frac{T-mg}{m}$

Given, $m=20kg$ and $g=10m/s^2$

Hence, $a=\frac{250-20\times 10}{20}$
$=\frac{50}{20}=2.5m/s^2$