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Standard VIII

Physics

Free Body Diagram

A Monkey of m...

Question

A Monkey of mass $20 k g$ is holding a vertical rope. The rope can break when a mass of $25 k g$ is suspended from it. What is the maximum acceleration with which the monkey can climb up along the rope?

7 {m s}^{- 2}

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10 {m s}^{- 2}

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5 {m s}^{- 2}

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2.5 {m s}^{- 2}

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Solution

The correct option is D $2.5 {m s}^{- 2}$
Here the breaking tension in rope is $T = 25 g = 250 N$
Let $a$ be the maximum acceleration of the monkey.
from FBD, $m a = T - m g$
or $a = \frac{T}{m} - g = \frac{250}{20} - 10 = 12.5 - 10 = 2.5 m / s^{2}$

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Q. A monkey of mass 40 kg climbs on a rope (Fig. 5.20) which can stand a maximum tension of 600 N. In which of the following cases will the rope break: the monkey (a) climbs up with an acceleration of 6 m s¯² (b) climbs down with an acceleration of 4 m s¯² (c) climbs up with a uniform speed of 5 m s¯¹ (d) falls down the rope nearly freely under gravity? (Ignore the mass of the rope).

A monkey of mass 20kg climbs on a rope which can stand a maximum tension of 300 N.in which of the following cases the rope breaks? The monkey

Options

Climbs up with an acceleration of 6m/s2

Climbs up with a uniform speed of 5m/s

Climbs down with an acceleration of 4m/s2

Falls down the rope nearly freely under gravity

Ans :1st option

A rope which can withstand a maximum tension of 400 N is hanging from a tree. If a monkey of mass 30 kg climbs up the rope, in which of the following cases will the rope break? Take $g = 10 m s^{- 2}$ and neglect the mass of the rope.

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A Monkey of mass 20kg is holding a vertical rope. The rope can break when a mass of 25kg is suspended from it. What is the maximum acceleration with which the monkey can climb up along the rope?

The correct option is D 2.5ms−2Here the breaking tension in rope is T=25g=250NLet a be the maximum acceleration of the monkey.from FBD, ma=T−mgor a=Tm−g=25020−10=12.5−10=2.5m/s2

A Monkey of mass $20 k g$ is holding a vertical rope. The rope can break when a mass of $25 k g$ is suspended from it. What is the maximum acceleration with which the monkey can climb up along the rope?

The correct option is D $2.5 {m s}^{- 2}$
Here the breaking tension in rope is $T = 25 g = 250 N$
Let $a$ be the maximum acceleration of the monkey.
from FBD, $m a = T - m g$
or $a = \frac{T}{m} - g = \frac{250}{20} - 10 = 12.5 - 10 = 2.5 m / s^{2}$