A monkey of mass 40 kg climbs on a massless rope which can stand a maximum tension of 500N. In which of the following cases will the rope break? (Take g=10ms−2)
A
The monkey climbs up with an acceleration of 5ms−2
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B
The monkey climbs down with an acceleration of 5ms−1
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C
The monkey climbs up with a uniform speed of 5ms−1
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D
The monkey falls down the rope freely under gravity.
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Solution
The correct option is D The monkey climbs up with an acceleration of 5ms−2 Here, mass of monkey, m=40 kg Maximum tension the rope can stand, T=500N Tension in the rope will be equal to apparent weight of the money (R). The rope will break when R exceeds T.
(a) When the monkey climbs up with an acceleration a=5ms−2 R=m(g+a)=40(10+5)=600N∴ R>T Hence, the rope will break.
(b) When the monkey climbs down with an acceleration a=5ms−2 R=m(g−a)=40(10−5)=200N∴ R <T Hence, the rope will not break.
(c) When the monkey climbs up with a uniform speed v=5 ms−1, its acceleration a=0 ∴ R=mg=40×10=400N∴ R<T Hence, the rope will not break.
(d) When the monkey falls down the rope freely under gravity, a=g ∴R=m(g−a)=m(g−g)=zero