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Question

A monkey of mass 40 kg climbs up a rope of breaking load 600 N, hanging from a ceiling. If it climbs up the rope with maximum possible acceleration, then the time taken by the monkey to climb up is:
(Length of the rope is 10 m and g=10 m/s2).

A
1 s
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B
3 s
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C
4 s
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D
2 s
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Solution

The correct option is D 2 s
Monkey will climb up with maximum acceleration (a), when it pulls the rope with maximum force which is equal to breaking strength 600 N.
Rope will pull monkey upwards with maximum force of 600 N.
i.e T=600 N
FBD of monkey:


Tmg=ma
60040×10=40a
a=20040=5 m/s2
Now, applying kinematic equation:
Length of rope l=10 m
10=ut+12at2=0+12×5×t2
5t2=20
t=4=2 s

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