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Question

A monkey staBeing on the ground wants to climb to the top of a vertical pole of 15m.he climbs 5m in 1s and slips downward 3m in next second. He keeps climbing up in this manner. Find the time taken by the monkey to climb to the top of the pole.

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Solution

In first 1 s, monkey climbs 5 meters,

In second 1 s, it slips down 3 meters.

So it climbs 2 meters every 2 s, except the last second. In the last second, it would cover all 5 meters and escape.

So keeping 1 s aside for last 5 meters.

Total distance to be covered is 15m, in which we subtract the last 5 m for the last climb.

So, to cover 10 m:

Time required=10/2 * 2 = 10 s

Adding that last 1 s, it takes 11 seconds.


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