A mono-electronic species in energy level with energy X was provided with excess of energy so that it jumps to higher energy level with energy Y. If it can emit 6 wavelengths originated from all possible transition between these groups levels, then which of the following relation is correct?
(Here n is the principle quantum of energy level X)

X / Y = (n - 1)^{2}

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X / Y = 1 + 3 / N

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\sqrt{(X / Y)} = 1 + 3 / N

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X / Y = N / 6

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Solution

The correct option is B $X / Y = (n - 1)^{2}$
Here given, max. no. of photon emited is 6.
$\frac{(n_{2} - n_{1}) (n_{2} - n_{1} + 1)}{2} = 6$
$X / Y = (n - 1)^{2}$

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Similar questions

Q. A mono electronic species in energy level with energy 'X' was provided with excess of energy so that it jumps to higher energy level with energy Y. If it can emit 6 wavelengths originated from all possible transitions between these groups levels, then which of the following relation is correct:
(Here n is the principal quantum of energy level X)

Q. A monoelectronic species in an energy level with an energy of X was provided with an excess of energy so that it jumps to a higher energy level having energy Y. If it can emit six wavelengths originating from all possible transitions between these group levels, then which of the following relation is correct?

Q. Hydrogen atom emits blue light when an electron in it jumps from

n = 4

energy level to

n = 2

energy level. Which colour of light would the atom emit when an electron in it jumps from

n = 5

level to the

n = 2

level?

What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n = 4 to an energy level with n = 2?

Energy above ground state

n = 3

------------------------------

6 e V

n = 2

------------------------------

4 e V

n = 1

------------------------------

0 e V

In above shown figure, the energy levels of a hypothetical atom are shown. Calculate the energy of photon emitted when a electron is making transition from the third energy level to the second energy level.

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The correct option is B X/Y=(n−1)2Here given, max. no. of photon emited is 6.(n2−n1)(n2−n1+1)2=6X/Y=(n−1)2

The correct option is B $X / Y = (n - 1)^{2}$
Here given, max. no. of photon emited is 6.
$\frac{(n_{2} - n_{1}) (n_{2} - n_{1} + 1)}{2} = 6$
$X / Y = (n - 1)^{2}$