A monoatomic gas at a pressure P, having a volume V expands isothermally to a volume 2V and then adiabatically to a volume 16V. The final pressure of the gas is (take γ=53)
A
64P
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B
32P
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C
P64
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D
16P
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Solution
The correct option is CP64 Let P1 be the pressure after isothermal expansion.
So, ⇒PV= Constant ⇒PV=P1(2V) ⇒P1=P2
Let Pf be the final pressure after adiabatical expansion.
So, ⇒PVγ= Constant⇒P1(2V)γ=Pf(16V)γ⇒Pf=P2(123)53⇒Pf=P(2)(2)5⇒Pf=P64