A monoatomic gas follows cyclic process ABCA, heat supplied to the gas in these steps are: for AB→x, for BC→y and for CA→z, then what is the efficiency of engine based on cyclic process ABCA. (B and C lie on same isothermal curve)
A
x+y−zx+y
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B
x+z−yx+z
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C
y+z−xy+z
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D
x+y+zx+y
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Solution
The correct option is Dx+y+zx+y For AB QAB=+x (heat added) For BC QBC=Δu↓0+Δw↓+ve=+y For CA QCA=z (but it is negative because heat is released) So, during AB and BC, heat is supplied to the system. Therefore, Qin=x+y. The work done by the sytem in a cylic process is summation of all the heat supplied. So, work done (W)= x+y+z.