A monoatomic gas of n-moles is heated from temperature T1 to T2 under two different conditions
(i) at constant volume and
(ii) at constant pressure.
The change in internal energy of the gas is :
A
More for (i)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
More for (ii)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Same in both cases
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Independent of number of moles
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C Same in both cases Change in internal energy will be △U=nCv△T for both process (at constant volume and constant pressure). It doesn't depend upon type of process. It is a state function, so change in temperature is same in both cases hence △U is same in both.