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Standard XII

Chemistry

Heat Capacity at Constant Volume

A monoatomic ...

Question

A monoatomic gas undergoes a process where gas does work on expense of internal energy. The relation between pressure and volume is given by

P V^{\frac{1}{3}} = C

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P V^{\frac{2}{3}} = C

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P V = C

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P V^{\frac{5}{3}} = C

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Solution

The correct option is D $P V^{\frac{5}{3}} = C$
Since $W = - Δ V$

$W + Δ V = 0$

$\Rightarrow Q = 0$

So, Adiabatic Process
$P V^{γ} = C$

$P V^{\frac{5}{3}} = C$ $(γ_{m o n o a t o m i c} = \frac{5}{3})$

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A monoatomic gas undergoes a process where gas does work on expense of internal energy. The relation between pressure and volume is given by

The correct option is D PV53=CSince W=−ΔV W+ΔV=0 ⇒Q=0 So, Adiabatic Process PVγ = C PV53=C (γmonoatomic=53)

The correct option is D $P V^{\frac{5}{3}} = C$
Since $W = - Δ V$

$W + Δ V = 0$

$\Rightarrow Q = 0$

So, Adiabatic Process
$P V^{γ} = C$

$P V^{\frac{5}{3}} = C$ $(γ_{m o n o a t o m i c} = \frac{5}{3})$