Question

A monoatomic gas undergoes an adiabatic process as indicated in the given figure. Find the work done during the process.

• A. ${10}^5\text{J}$
• B. $2\times {10}^5\text{J}$
• C. $3\times {10}^5\text{J}$
• D. $4\times {10}^5\text{J}$

Answer 1

The correct option is C $3\times {10}^5\text{J}$

Since the given system is monoatomic, we get $\gamma =\frac{5}{3}$
Work done during adiabatic process,
$W=\frac{P_F{V}_F-P_i{V}_i}{1-\gamma }$
$=\frac{2\times {10}^5-4\times {10}^5}{1-\frac{5}{3}}$
$=3\times {10}^5\text{J}$