A monoatomic ideal gas follows the process-TV 3-2- constantThe molar specific heat for this process is 5 R - y - where R is the gas constant- Find the value of y- Answer upto two digit after decimal point

TV^3/2 = constant (PV)V^3/2/nR = constant PV^5/2 = constant PV^x = constant x = 5/2 For polytropic process, C = C_V + R/1 x C_V=f/2R=3R/2 C =3R/2 + R/1 5/2 = ...

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Standard XII

Chemistry

Irreversible Adiabatic Expansion And Compression

A monoatomic ...

Question

A monoatomic ideal gas follows the process:
$T V^{\frac{3}{2}} =$ constant
The molar specific heat for this process is $(\frac{5 R}{y})$ , where R is the gas constant. Find the value of $y$ . (Answer upto two digit after decimal point)

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Solution

$T V^{\frac{3}{2}} =$ constant
$\frac{(P V) V^{\frac{3}{2}}}{n R}$ = constant
$P V^{\frac{5}{2}}$ = constant
$P V^{x}$ = constant
$x = \frac{5}{2}$
For polytropic process,
$C = C_{V} + \frac{R}{1 - x}$
$C_{V} = \frac{f}{2} R = \frac{3 R}{2}$
$C = \frac{3 R}{2} + \frac{R}{1 - \frac{5}{2}} = \frac{5 R}{6} .$

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A monoatomic ideal gas follows the process: TV32= constant The molar specific heat for this process is (5Ry), where R is the gas constant. Find the value of y. (Answer upto two digit after decimal point)

TV32= constant (PV)V32nR = constant PV52 = constant PVx = constant x=52 For polytropic process, C=CV+R1−x CV=f2R=3R2 C=3R2+R1−52=5R6.

A monoatomic ideal gas follows the process:
$T V^{\frac{3}{2}} =$ constant
The molar specific heat for this process is $(\frac{5 R}{y})$ , where R is the gas constant. Find the value of $y$ . (Answer upto two digit after decimal point)