A monoatomic ideal gas is taken through a cycle ABCA as shown. The efficiency of the cycle is

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10%

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8.7%

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15%

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Solution

The correct option is C
8.7%

Work done = Area = $\frac{1}{2} \times P \times 2 V = P V$

$Q_{A B} = n C_{v} Δ T = \frac{C_{v}}{R} V (2 P - P) = \frac{3 P V}{2}$

$Q_{B C} = n C_{P} Δ T = \frac{C_{p}}{R} 2 P (3 V - V) = 10 P V$

$η = \frac{W}{Q} = \frac{2 P V}{23 P V} \times 100 = 8.7 %$

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