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Question

A monobasic acid A has neutralization equivalent 116 and does not decolorize Bayer's regent. Also, A is enantiomeric. A on treatment with Br2/red phosphorus produces B which is still resolvable. B on dehydrobromination produced C which shows stereoisomerism C on decarboxylation produced. D which does not show stereoisomerism. Deduce structures of A, B, C, and D.

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Solution

  • PBr3 will attach the Br at the suitable substitute H of compound A.
  • In the presence of alc. KOH dehydrohalogenation will occur and form the product C, it is showing stereoisomerism i.e. cis and trans.
  • After decarboxylation final product D will form.

1010974_205609_ans_df89017c8c6c45c5a0f7223a9ce37ab2.PNG

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