Given : μ=1.33
λa=589 nm
As μ=cv
v = cμ=3×1081.33
Speed, v = 2.26×108 m/s
As the frequency remains same,
∴ v = cλa=3×108589×10−9
Frequency v = 5.09×1014Hz
Wavelength, λw=vν
= 2.26×1085.09×1014
= 444 nm
(b) Given : μ=1.55,f=20cm
We know that ,
1f=(μ−1)(1R1−1R2)120=(1.55−1)(1R+1R)120=0.55×2RR=20×0.55×2R=22 cm