A monochromatic source of light operating at 200 W emits 4-1020 photons per second- The wavelength of this light will be nm-

The energy of each photon is = 200 J s^ 1/4×10^20 s^ 1 = 5 ×10^ 19J. Wavelength = λ = hc/E = (6.63×10^ 34J s)× (3×10^8ms^ 1)/(5×10^ 19J) =4.0×10^ 7m = 400 n ...

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Standard XII

Physics

Stopping Potential Revisited

A monochromat...

Question

A monochromatic source of light operating at 200 W emits $4 \times 10^{20}$ photons per second. The wavelength of this light will be __ nm.

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Solution

$The energy of each photon is = \frac{200 J s^{- 1}}{4 \times 10^{20} s^{- 1}} = 5 \times 10^{- 19} J . W a v e l e n g t h = λ = \frac{h c}{E} = \frac{(6.63 \times 10^{- 34} J s) \times (3 \times 10^{8} m s^{- 1})}{(5 \times 10^{- 19} J)} = 4.0 \times 10^{- 7} m = 400 n m .$

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A monochromatic source of light operating at 200 W emits 4×1020 photons per second. The wavelength of this light will be __ nm.

The energy of each photon is=200J s−14×1020 s−1=5×10−19J.Wavelength=λ=hcE=(6.63×10−34J s)×(3×108ms−1)(5×10−19J)=4.0×10−7m=400 nm.

A monochromatic source of light operating at 200 W emits $4 \times 10^{20}$ photons per second. The wavelength of this light will be __ nm.

$The energy of each photon is = \frac{200 J s^{- 1}}{4 \times 10^{20} s^{- 1}} = 5 \times 10^{- 19} J . W a v e l e n g t h = λ = \frac{h c}{E} = \frac{(6.63 \times 10^{- 34} J s) \times (3 \times 10^{8} m s^{- 1})}{(5 \times 10^{- 19} J)} = 4.0 \times 10^{- 7} m = 400 n m .$