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Question

A monoprotic acid in 1.00M solution is 0.001% ionised. The dissociation constant of acid is:

A
1×103
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B
1×106
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C
1×108
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D
1×1010
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Solution

The correct option is D 1×1010
According to Ostwald's dilution law
K=α2C(1α)
As degree of ionisation is very less than 1 so above equation reduces to
K=Cα2
K=1(105)2
K=1010

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