A month is selected at random in a year. The probability that it is March or October, is

(a) $\frac{1}{12}$

(b) $\frac{1}{6}$

(c) $\frac{3}{4}$

(d) None of these

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Solution

GIVEN: A month is selected at random in a year.

TO FIND: Probability that it is March or October

Total months in a year is 12

Hence total number of favorable outcome is 2 i.e. March or October

We know that PROBABILITY =

Hence probability that the month selected is March or October is equal to

Hence the correct option is

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