A mosquito flaps its long front wings up to 600 times per second, what is the time period of the flaps?

0.0016 s

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0.16 s

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600 s

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1200 s

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Solution

The correct option is A $0.0016 s$
Time period is the time required to complete one oscillation. One to and fro flap of a mosquito can be called one oscillation.

Therefore, $T i m e p e r i o d = \frac{T i m e t a k e n}{N u m b e r o f o s c i l l a t i o n s} = \frac{1}{600} = 0.0016 s$

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