A motor boat going down stream overcomes a float at a point A. 60 minutes later it turns and after some time passes the float at a distance of 12 km from the point A. The velocity of the stream is (assuming constant velocity for the boat in still water)
6 km/h
Let boat velocity w.r.t. water be 'v'
and water velocity in river be 'u'
then,~AC=(v+u)1 .......(1)
Assume time taken by boat to cover path C to B be 't'
then, BC=(v−u)t ........(2)
and AB=u(t+1)=12 km ..............(3)
Now, AC = AB + BC
⇒v+u=ut+u+vt−ut
⇒t=1 hour
and u=6 km/h