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Standard XII

Physics

1st Law of Thermodynamics

A motor can p...

Question

A motor can pump up water to fill a tank of volume $50 m^{3}$ in $25$ minutes which is placed at of $20 m$ . If efficiency of the motor is $40 %$ calculate the power of the motor.

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Solution

Power of motor, $P = \frac{1}{η} \frac{ρ V g h}{t}$

Where,

$ρ$ = Density, $V$ = Volume, $h$ = Heigth $t$ = Time and $η$ =efficiency of motor

$P = \frac{1}{0.4} \frac{1000 \times 50 \times 10 \times 20}{25 \times 60} = 16666.67 J$

$P = \frac{16666.67}{746} = 22.23 h p$

Power of motor is $22.23 h p$

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A motor can pump up water to fill a tank of volume 50 m3 in 25 minutes which is placed at of 20 m. If efficiency of the motor is 40% calculate the power of the motor.

Power of motor, P=1ηρVght Where, ρ = Density,V = Volume, h = Heigth t = Time and η =efficiency of motor P=10.41000×50×10×2025×60=16666.67 J P=16666.67746=22.23hp Power of motor is 22.23 hp

A motor can pump up water to fill a tank of volume $50 m^{3}$ in $25$ minutes which is placed at of $20 m$ . If efficiency of the motor is $40 %$ calculate the power of the motor.