A motor car moving with a uniform speed of $20 m / s e c$ comes to stop on the application of breakes after travelling a distance of $10 m$ . Its acceleration is

20 m / s e c^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 20 m / s e c^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 40 m / s e c^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ 2 m / s e c^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

A motor car moving with a uniform speed of $20 m s^{- 1}$ comes to rest on the application of brakes after travelling a distance of 10 m. Its acceleration is

Q. The velocity of a body moving with a uniform acceleration of

2 m / s e c^{2}

10 m / s e c

. Its velocity after an interval of 4 sec is

A car is moving with speed 30 m/sec on a circular path of radius 500 m.
Its speed is increasing at the rate of 2m/ $s e c^{2}$ , What is the acceleration of the car

Q. A body was initially moving with

10 m / s e c

and it starts acceleration with

2 m / s e c^{2}

, the distance covered by it in

10 s e c

will be

Q. A car moves north with a speed of

20 m s^{- 1}

. It changes its direction to east and moves with a speed of

20 m s^{- 1}

. What is its velocity now ?

Join BYJU'S Learning Program

A motor car moving with a uniform speed of 20m/sec comes to stop on the application of breakes after travelling a distance of 10m. Its acceleration is

A motor car moving with a uniform speed of $20 m / s e c$ comes to stop on the application of breakes after travelling a distance of $10 m$ . Its acceleration is