A motor car of mass 1200 kg is moving along a straight line with a uniform velocity of 90 kmph. Its velocity is slowed down to 18 kmph in 4 seconds by an external force. The acceleration of the body is:
−5 ms−2
Given, initial velocity (u)=90 kmph = 90×518=25 ms−1
Final velocity (v)=18 kmph = 18×518=5 ms−1
Mass of car = 1200 kg
Time (t) = 4 s
We know, acceleration (a)=v−ut
So, a=5−254=−5 ms−2