Question

A motor cycle driver doubles its velocity when he is having a turn. The force exerted outwardly will be

• A. Double
• B. Half
• C. 4 times
• D. $\frac{1}{4}times$

Answer 1

The correct option is C

4 times

$F=\frac{m{v}^2}{r}\Rightarrow F\propto v^2$ i.e. force will become 4 times.