A motor cycle engine delivers a power of 10 kW by consuming petrol at the rate of 2.4 kg/hour. If the calorific value of petrol is 35.5 MJ/kg, the rate of heat rejection by the exhaust is
A
5.5 kW
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B
13.7 kW
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C
11.2 kW
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D
9.7 kW
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Solution
The correct option is B 13.7 kW Heat received (or produced by the burning of petrol) in one hour will be =(2.4kg/hour)(35.5MJ/kg)=85.2×106J/hour ∴ The rate at which heat is received =85.2×106(3600s)=2.367×104J/s=23.67kW Evidently, the rate of heat rejection = rate at which heat is produced - rate at which work is obtained = 23.67kW−10kW=13.67kW≃13.7kW