Question

A motor driving a solid circular steel shaft transmits 40 kW of power at 500 rpm. If the diameter of the shaft is 40 mm, the maximum shear stress in the shaft is ______ MPa.

• A. 60.792

Answer 1

The correct option is A 60.792
$T=\frac{P\times 60\times {10}^6}{2\pi N}=\frac{40\times 60\times {10}^6}{2\pi \left(500\right)}$

= 763943.7268 N-mm

${\tau }_{max}=\frac{16T}{\pi d^3}=\frac{16\times 763943.7268}{\pi (40{)}^3}$

= 60.792 MPa