A motor of 100 H.P. moves a load with a uniform speed of 72 km/hr. The forward thrust applied by the engine on the car is

1111 N

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3550 N

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2222 N

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3730 N

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Solution

The correct option is C 3730 N
$F o r w a r d t h r u s t, F = \frac{P}{v} = \frac{100 \times 746}{20} = 3730 N$

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A motor of 100 H.P. moves a load with a uniform speed of 72 km/hr. The forward thrust applied by the engine on the car is

The correct option is C 3730 NForwardthrust,F=Pv=100×74620=3730N

The correct option is C 3730 N
$F o r w a r d t h r u s t, F = \frac{P}{v} = \frac{100 \times 746}{20} = 3730 N$