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1st Equation of Motion

A motorbike i...

Question

A motorbike initially at rest, picks up a velocity of $72 k m / h^{- 1}$ over a distance of $40 m$ . Calculate (1)acceleration (2)time in which it picks up above velocity

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Solution

$\begin{matrix} u = 0 v = 72 k m / m = 72 \times \frac{5}{18} = 20 m / s v^{2} = u^{2} + 2 a s 20 \times 20 = 0 + 2 \times 40 \times a a = 5 m / s^{2} v = u + a t 20 - 0 = a t t = 4 sec \end{matrix}$

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