A motorboat moves at a steady speed of $6 m s^{- 1}$ .Water resistance acting on it is $500 N$ . Calculate the power of the engine.

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Solution

Step 1: Data provided,
$F o r c e (F) = 500 N S p e e d (v) = 6 m s^{- 1}$
Step 2: Formula used,
$P o w e r (P) = F o r c e (F) \times v e l o c i t y (v)$
Step 3: Calculation,
$P o w e r (P) = F o r c e (F) \times v e l o c i t y (v) P = 500 N \times 6 m s^{- 1} = 3000 W$
Hence, the required power of the engine is $3000 W$

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A motorboat moves at a steady speed of6ms-1 .Water resistance acting on it is 500N . Calculate the power of the engine.

Step 1: Data provided,Force(F)=500NSpeed(v)=6ms-1Step 2: Formula used,Power(P)=Force(F)×velocity(v)Step 3: Calculation,Power(P)=Force(F)×velocity(v)P=500N×6ms-1=3000WHence, the required power of the engine is 3000W

A motorboat moves at a steady speed of $6 m s^{- 1}$ .Water resistance acting on it is $500 N$ . Calculate the power of the engine.