A motorboat that has a speed of 9 km/hr in still water, goes 15 km downstream and comes back in 3 hours 45 minutes. The speed of the stream is
Let T and t denote the time taken for downstream and upstream journeys respectively.
Then, T+t=3 hrs 45 min =154 hrs.
Let v be the speed of the stream.
⇒Speed downstream=9+v and
Speed upstream=9−v.
⇒T=159+v ....(1) and
t=159−v ...........(2)
Adding (1) and (2), we get
159+v+159−v=T+t=154.
⇒19+v+19−v=14
⇒9−v+9+v81−v2=14
⇒v2−9=0
⇒(v+3)(v−3)=0
Since speed cannot be negative, we must have v=3 kmph.
Thus, the speed of the stream is 3 kmph.