The correct option is A 6000 N
Mass of the motor car, m=1200 kg
Initial velocity of the motor car,
u=90 km/h
u=90×1000/3600 m/s
u=25 m/s
Final velocity of the motor car,
v=18 km/h
u=18×1000/3600 m/s
v=5 m/s
Time taken, t=4 s
Using equation of motion:
v=u+at
5=25+4a
a=−5 m/s2
Negative sign indicates that its a retarding motion i.e., velocity is decreasing.
Using second law of motion,
F=ma
F=1200×−5 N
F=−6000 N
Negative force here is indicating that the force is opposing motion.