Dear Student,
Let mass of Bus =M
mass of Motorcycle=m
velocity of Bus =v
velocity of Motorcycle =V
we know M>m.
Given Same Momentum i.e. Mv=mV
M/m=V/v
V>v
velocity of Motorcycle > velocity of Bus
now kinetic energy is given by mv2/2
k.E for Bus =Mv2/2=Mv.v/2 ...............(1)
k.E for Motorcycle =mV2/2=mV.V/2 ................(2)
from eqn (1) and (2) we can see that
we know
Mv=mV
so just have to compare
V/2 and v/2
we also know V>v
so V/2>v/2
from this we can conclude that
k.E for Motorcycle >k.E for Bus
Regards