A motorcycle is being driven at a speed of 20 m/s when brakes are applied to bring it to rest in five seconds. The deceleration produced in this case will be :

(a) $+ 4 m s^{2}$

(b) $- 4 m s^{2}$

(c) $+ 0.25 m s^{2}$

(d) $- 0.25 m s^{2}$

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Solution

In this case,

u (Initial Velocity) = 20 m/sec
v (final velocity) = 0 m/sec (at rest)
time (t) = 5 secs

$a equals fraction numerator v minus u over denominator t end fraction a equals fraction numerator 0 minus 20 over denominator 5 end fraction a equals fraction numerator negative 20 over denominator 5 end fraction a equals negative 4 space bevelled m over s squared$

Therefore Deceleration produced is
option a is correct

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A motorcycle is being driven at a speed of 20 m/s when brakes are applied to bring it to rest in five seconds. The deceleration produced in this case will be : (a) +4 m s2 (b)−4 m s2 (c) +0.25 m s2 (d) −0.25 m s2

In this case, u (Initial Velocity) = 20 m/sec v (final velocity) = 0 m/sec (at rest) time (t) = 5 secs Therefore Deceleration produced is option a is correct

A motorcycle is being driven at a speed of 20 m/s when brakes are applied to bring it to rest in five seconds. The deceleration produced in this case will be :

(a) $+ 4 m s^{2}$

(b) $- 4 m s^{2}$

(c) $+ 0.25 m s^{2}$

(d) $- 0.25 m s^{2}$