wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A motorcycle is going on an over-bridge of radius R. The driver maintains a constant speed. As the motorcycle is ascending on the over-bridge, the normal force on it


A

Increases

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

Decreases

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

Remains the same

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

Fluctuates

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

Increases


Lets take 3 points on the ascending side of the circular bridge

The motorcycle is going with constant velocity.

So it will have a centripetal acceleration of v2R always

At A: mg cos θ2 NA = mv2R

NA=mg cosθ2 mv2R ......... (i)

Similarly

NB=mg cosθ2 mv2R ......... (ii)

NC=mg mv2R ( at topmost point ) ....... (iii)

θ2>θ1

So cos θ2 < cos θ1

now comparing all 3 equations we get

NC > NB > NA

So as the motorcycle is going up, the normal on it by bridge is increasing.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circular Motion: A Need for Speed
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon