A motorcycle was bought at Rs. $50, 000$ . The value depreciated at the rate of $8$ % per annum. Find the value after one year.

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Solution

$C o s t p r i c e = R s 50000 = P r i n c i p a l v a l u e$
$R a t e (R) o f d e p r e c i a t i o n = 8 %$
$T = 1 y e a r$
$∴ A = P (1 - \frac{R}{100})^{T} s i n c e v a l u e d e p r e c i a t e s,$
$=> A = 50000 (1 - \frac{8}{100})$
$= 50000 \times \frac{23}{25}$
$= 46000$
$∴ v a l u e o f m o t o r c y c l e a f t e r o n e y e a r i s R s .46000$

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