A motorcycle wheel has a radius of 14 cm. The distance covered by the wheel after 2 full rotations is .
$(π = \frac{22}{7})$

176 cm

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166 cm

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156 cm

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170 cm

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Solution

The correct option is A 176 cm
1 complete rotation $=$ circumference of the wheel $= 2 \times π \times r$ [where, $r$ is radius]
Given, r = 14 cm
So, Distance covered $= 2 \times (2 π \times r)$
$= 2 (2 \times \frac{22}{7} \times 14)$
$\Rightarrow$ Distance covered $= 176 c m$

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Similar questions

A bicycle wheel has a diameter of $7 c m .$ What distance does the wheel cover on the ground if it completes 1 full rotation?

$(Take π = \frac{22}{7})$

Q. A bicycle wheel has a diameter of 7 cm. What distance does the wheel cover on the ground if it completes 1 full rotation?
(Assume

π = \frac{22}{7}

)

Q. Distance covered by a wheel of radius 14 cm in one rotation is .

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A bicycle wheel has a diameter of 7 cm. What distance does the wheel cover on the ground if it completes 1 full rotation?

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A motorcycle wheel has a radius of 14 cm. The distance covered by the wheel after 2 full rotations is . (π=227)

The correct option is A 176 cm1 complete rotation = circumference of the wheel =2×π×r [where, r is radius] Given, r = 14 cm So, Distance covered =2×(2π×r) =2(2×227×14) ⇒ Distance covered =176 cm

A motorcycle wheel has a radius of 14 cm. The distance covered by the wheel after 2 full rotations is .
$(π = \frac{22}{7})$

The correct option is A 176 cm
1 complete rotation $=$ circumference of the wheel $= 2 \times π \times r$ [where, $r$ is radius]
Given, r = 14 cm
So, Distance covered $= 2 \times (2 π \times r)$
$= 2 (2 \times \frac{22}{7} \times 14)$
$\Rightarrow$ Distance covered $= 176 c m$