A motorcyclist drives from A to B with a uniform speed of $30 k m / h$ and returns with a speed of $20 k m / h$ . Find its average speed.

5 k m / h

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0 k m / h

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25 k m / h

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24 k m / h

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Solution

The correct option is C $24 k m / h$
Let the Distance between A and B be $x$
Time taken from A to B, $t_{1} = \frac{x}{30}$
Time taken from B to A, $t_{2} = \frac{x}{20}$
Total time $= t_{1} + t_{1} = \frac{x}{30} + \frac{x}{20} = \frac{5 x}{60}$
Average speed $= \frac{t o t a l d i s t a n c e}{t o t a l t i m e} = \frac{x + x}{\frac{5 x}{60}} = \frac{2 x}{\frac{5 x}{60}}$ $= 24 k m h^{- 1}$

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