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Question

A motorcyclist drives from place A to B with a uniform speed of 30 km h1 and returns from place B to A with a uniform speed of 20 km h1. Find his average speed.

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Solution

Let distance between A and B is D
Then, time taken by motorcyclist with uniform speed 30 km/h

T₁ = fraction numerator d i s tan c e space over denominator s p e e d end fraction = d over 30hrs

Again, they return with uniform speed 20 km , so time taken by motorcyclist , T₂ = D over 20

Now,

average speed of motorcyclist = fraction numerator t o t a l space d i s tan c e over denominator t o t a l space t i m e end fraction


= fraction numerator D plus D over denominator begin display style D over 20 plus D over 30 end style end fractionkm/h





= 24 km/h


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