Question

A motorcyclist moving with a velocity of $72km{h}^{-1}$ on a flat road takes a turn at a point where the radius of curvature of the road is 20 m. In order to avoid sliding, he must not bend with respect to the vertical by an angle $\theta$ greater than ( g= 10 $m{s}^{-2}$):

• A. $ta{n}^{-1}6$
• B. $ta{n}^{-1}2$
• C. $ta{n}^{-1}25.92$
• D. $ta{n}^{-1}4$

Answer 1

The correct option is B $ta{n}^{-1}2$

Velocity of motopr cycle $=v$

Radius of curvature$=r$

Acceleration due to gravity$=g$

$v=\frac{5}{18}\times 72$

$v=20m/s$

from $tan\mu =\frac{v^2}{rg}=\frac{{20}^2}{20\times 10}=2⟹\mu =ta{n}^{-1}\left(2\right)$