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Standard VII

Physics

Measurement of Time

A motorist dr...

Question

A motorist drives north for $35.0$ minutes at $85.0 k m / h$ and then stop for $15.0$ minutes. He next continues north, travelling $130 k m$ in $2.00 h o u r s$ . What is his total displacement :

85 k m

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179.6 k m

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20 k m

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140 k m

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Solution

The correct option is B $179.6 k m$
Given,

Displacement in first event $= s p e e d \times t i m e = 85 \times \frac{35}{60} = 49.58 k m$

Displacement in second event $= 130 k m$

Net displacement $D = 49.58 + 130 = 179.58 k m$

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A motorist drives north for 35.0 minutes at 85.0 km/h and then stop for 15.0 minutes. He next continues north, travelling 130 km in 2.00 hours. What is his total displacement :

The correct option is B 179.6 kmGiven, Displacement in first event = speed×time=85×3560=49.58km Displacement in second event = 130 km Net displacement D=49.58+130=179.58km

A motorist drives north for $35.0$ minutes at $85.0 k m / h$ and then stop for $15.0$ minutes. He next continues north, travelling $130 k m$ in $2.00 h o u r s$ . What is his total displacement :

The correct option is B $179.6 k m$
Given,

Displacement in first event $= s p e e d \times t i m e = 85 \times \frac{35}{60} = 49.58 k m$

Displacement in second event $= 130 k m$

Net displacement $D = 49.58 + 130 = 179.58 k m$