wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

A moves with 65km/h while B is coming back of A with 80km/h. The relative velocity of B with respect to A is


A

80km/h

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

60km/h

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

15km/h

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

145km/h

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

145km/h


Step 1: Given Data:

Assuming the direction of A as negative,

Velocity of VA=-65km/h

Velocity of VB=80km/h

Since the velocity of A and velocity of Bare in the opposite direction. So, the velocity A is taken as negative and the velocity of B is taken as positive.

Step 2: Formula Used:

VAB=VA-VB

Where, VA=Velocity of A

VB=Velocity of B

VAB=Velocity of A relative to B

Step 3: Calculating the relative velocity:

The velocity of B relative to A,

VBA=VB-VA

=80km/h--65km/h

=145km/h

Hence, option D is the correct answer.


flag
Suggest Corrections
thumbs-up
11
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon